A 3.50 Liter Gas Sample At 20c And Pressure Of 650.0 Mmhg

A 3.50 liter gas sample at 20c and pressure of 650.0 mmHg

 

Good Day.

Problem:

A 3.50 liter gas sample at 20c and pressure of 650.0 mmHg

Note:

Convert degree celsius to kelvin when solving gas laws problem.

kelvin = degree celsius + 273.15

kelvin = 20 + 273.15 = 293.15 K

Given Data:

n (amount in moles) = ? unknown

T (temperature kelvin) = 20°C 293.15 K

P (pressure)   = 650.0 mmHg

V (volume)    = 3.50 liter

R (for mmHg unit of pressure) = 62.4 mmHg.L/mol.K

Solution:

We can used the formula for ideal gas law which is PV=nRT

To solve for n, we can use n = PV/RT

n = PV/RT

  = 650.0 mmHg × 3.50 liter / 62.4 mmHg . L / mol.K × 293.15 K

   = 2275 / 18292.56  /mol

   = 0.124 mol

Answer:

Amount of gas in mole is 0.124 mole

Hope it helps...=)


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